mbcobretti
Banned User
- Joined
- Dec 12, 2006
- Location
- Dakota
Hello everyone!
I know it's impossible to find a system that will always win, but here is an idea of a system that actually might be fruitfull. Hope someone has enough time and patience to implement it.
First of all, there is one argument against those who believe that the house advantage cannot be overcome - house advantage relates to the NUMBER OF WINNING SPINS HOUSE HAS OVER THE PLAYER, and not the money you put in a game. This means that the house wins approximatelly 52.5 times in a 100 spins series, while the player has 47.5 wins. If player wins 1.5 chip each time, and loses 1 chip when the house wins, who's ahead?
That is one thing! The other relates to odds. It is very common opinion that each spin represents an isolated event, and each time you bet on red you have around 47.5% of chance for winning. However, what is the probability of the tenth red in a row? It is actually simple to calculate:
0.475x0.475x0.475x0.475 (and so on... 10 times...)=0.0007 (0.07%). This probability is rather low, but it's not impossible.
Ok, now back to the system proposal. As you probably know by now, it is very rare (if not impossible) to have a streak of more than 25 different numbers. Hence the system basis - simply follow last numbers that came out, and sooner or later you'll hit a winner.
let's here what you have to say about it...
I know it's impossible to find a system that will always win, but here is an idea of a system that actually might be fruitfull. Hope someone has enough time and patience to implement it.
First of all, there is one argument against those who believe that the house advantage cannot be overcome - house advantage relates to the NUMBER OF WINNING SPINS HOUSE HAS OVER THE PLAYER, and not the money you put in a game. This means that the house wins approximatelly 52.5 times in a 100 spins series, while the player has 47.5 wins. If player wins 1.5 chip each time, and loses 1 chip when the house wins, who's ahead?
That is one thing! The other relates to odds. It is very common opinion that each spin represents an isolated event, and each time you bet on red you have around 47.5% of chance for winning. However, what is the probability of the tenth red in a row? It is actually simple to calculate:
0.475x0.475x0.475x0.475 (and so on... 10 times...)=0.0007 (0.07%). This probability is rather low, but it's not impossible.
Ok, now back to the system proposal. As you probably know by now, it is very rare (if not impossible) to have a streak of more than 25 different numbers. Hence the system basis - simply follow last numbers that came out, and sooner or later you'll hit a winner.
let's here what you have to say about it...
