Faultless Blackjack Strategy!

KasinoKing

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Faultless or Faulty? Can any Blackjack wizards help me?

Ive played Blackjack hundreds of times online & in B&M casinos but theres still one thing I can not understand thats really bugging me (apart from why do I always lose!);
Assuming a completely fair game with truly random cards, if the player plays to the exact same rules as the dealer (i.e. regardless of what the dealers showing, the player draws to 17+, doesnt split or double), then surely logic says the chances of winning a hand MUST be precisely 50/50.
Question 1 Do you agree?

On the assumption that the above is correct; when dealer hits BJ, player loses 1 x stake, but when player hits BJ he wins 1.5 x stake. Therefore, logically, playing this strategy must mean the player will always win in the long run!
Obviously there must be a hole in my logic somewhere (big enough to drive a bus through), or everyone would be doing it (including me!). But I cant see it.
So question 2 is: Which part of the above logic is incorrect? (i.e. What exactly is it that gives the house the edge???).

By the way, I havent actually trailed this yet so theres a million to 1 chance I have just unlocked the secret of the universe! (Or at least, the secret of Blackjack!)
 
The catch is when you bust and the dealer also busts!!

You lose your bet even though you technically drew with both busting.

This happens about 5% of the time hence playing like that will cost you $5 for every hundred. :D
 
From Wizard of Odds' site:

Mimic the dealer: For my analysis of this strategy I assumed the player would always hit 16 or less and stand on 17 or more. The player as well as dealer stood on soft 17. The player never doubled or split, since the dealer is not allowed to do so. This results in a house edge of 5.48%.

Maybe you can email him and ask for a more detailed explanation of how he came by that dealer's edge.
 
If the game is fair and you know how to play and have good money management skills you can win. and if you not winnng you need to sign up for my class
 
The house edge probably results from something as simple as the player has to go first. Because you potentially can bust first, the casino wins.
 
"The house edge probably results from something as simple as the player has to go first"

Thats it in a nutshell.

If you took it in turns to go first, dealer/player/dealer/player, then you would get a 50/50 game by mimicing the dealer.

But the player always takes the first risk.
 
eek said:
"The house edge probably results from something as simple as the player has to go first"

Thats it in a nutshell.

If you took it in turns to go first, dealer/player/dealer/player, then you would get a 50/50 game by mimicing the dealer.

But the player always takes the first risk.

That's a very interesting idea!
It's a shame it's utter rubbish!!! :lolup:

If the dealer went first & bust, would you, the player, carry on trying to draw cards to 17+ ??? :)
I can't see many casino's taking your idea up!
 
Last edited:
KasinoKing said:
That's a very interesting idea!
It's a shame it's utter rubbish!!! :lolup:

If the dealer went first & bust, would you, the player, carry on trying to draw cards to 17+ ??? :)
I can't see many casino's taking your idea up!
If the player were forced to follow the same strategy as the dealer when going second, then it would be a fair game, and totally boring, too. With 0 house edge it still would not be of interest to the casinos.
 
If its any comfort I remember my first casino blackjack experiance 15 years ago. I played exactly how you described and boy did it pi$$ everyone on my table off!!

At that time my logic was exactly the same as yours in the first post :D :D
 

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