Is someone able to do the math for me?

lucky21

Dormant account
Joined
Jun 12, 2006
Location
australia
Hi
Is there anybody who would have time to do some probability math for me?

what are the chances/odds of betting on 2 seperate dozens in european roulette and having the ball fall on the dozen your not betting on 9 times in a row.

cheers
 
what are the chances/odds of betting on 2 seperate dozens in european roulette and having the ball fall on the dozen your not betting on 9 times in a row.
Yep - the odds are 0.00816% - or once in every 12,225 spins.
(That's including the Zero being a number you don't want to hit)

KK
 
If you formulate the question other way, you will get:


On your first spin the chances are 24/37 * 100 = 64.864 % to hit the winning dozen.
Or 13/37 * 100 = 35.135% not to hit it.


After the 8 spins in which the ball landed on the only one dozen you are not betting (or zero), the chances (on your 9th spin) are:


24/37 * 100 = 64.864 % to hit the winning dozen.
Or 13/37 * 100 = 35.135% not to hit it.
Exactly the same.
 

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