Is someone able to do the math for me?

**lucky21** · 26th November 2009, 11:33 PM

Hi
Is there anybody who would have time to do some probability math for me?

what are the chances/odds of betting on 2 seperate dozens in european roulette and having the ball fall on the dozen your not betting on 9 times in a row.

cheers

**KasinoKing** · 26th November 2009, 11:40 PM

Originally Posted by lucky21

what are the chances/odds of betting on 2 seperate dozens in european roulette and having the ball fall on the dozen your not betting on 9 times in a row.

Yep - the odds are 0.00816% - or once in every 12,225 spins.
(That's including the Zero being a number you don't want to hit)

KK

**ultra100** · 27th November 2009, 12:51 AM

If you formulate the question other way, you will get:

On your first spin the chances are 24/37 * 100 = 64.864 % to hit the winning dozen.
Or 13/37 * 100 = 35.135% not to hit it.

After the 8 spins in which the ball landed on the only one dozen you are not betting (or zero), the chances (on your 9th spin) are:

24/37 * 100 = 64.864 % to hit the winning dozen.
Or 13/37 * 100 = 35.135% not to hit it.
Exactly the same.