
Originally Posted by
nafanny29
I was wondering what are the odds of completing a Royal Flush by the river (Holdem) when playing 2 Royal cards ie. AKs, QTs etc
If I understand it correctly, you assume that you have two of the cards for the RF and you want to know the probability that the remaining 3 cards will show up among the 5 community cards.
Using excel notation, combin(50,5)=2118760 ways of choosing the 5 community cards out of the 50 unseen cards, disregarding order. Three of these cards are fixed, and there are combin(47,2)=1081 ways of choosing the other 2 out the remaining 47. This makes the probability of having a RF 1081/2118760=1/1960=0.00051.
It does not matter that there are other people at the table or how many there are, unless you know something about their cards.
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