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Thunderstruck II and Wilds.

Discussion in 'Online Casinos' started by Setag, Aug 20, 2010.

    Aug 20, 2010
  1. Setag

    Setag Dormant account

    Occupation:
    Game Designer
    Location:
    London
    Hi all.

    Seem to recall we have some avid Thunderstruck II players on here so I have this question. It relates to a win scenario I had, playcheck isnt working at the mo so cant check that either!

    So the game is 243 ways to win....

    I got WILD WILD WILD on reels 1,2 and 3 respectively.

    Reel 4 had 10/9/castle symbol on it.

    Im sure i got cheated out of money...

    What ways should I have been paid? ONLY for 3x wild.... once?

    or for 4 of a kind, 10, 9, castle?

    so confused as to how the wilds are used in this.
     
  2. Aug 20, 2010
  3. retlaw

    retlaw Meister Member

    Occupation:
    Retired
    Location:
    Earth
    I think, but I am not sure :

    27 times 4 "10" ; 27 times 4 "9" ; 27 times 4 "castle"
     
  4. Aug 20, 2010
  5. Rusty

    Rusty Banned User - repetitive flaming

    Occupation:
    IT
    Location:
    Manchester UK
    Correct, unless 3 wilds is the greater win than any of the above.
    4 reels is 81 pay lines(3x3x3x3)=81 the 5th reel (81x3) makes up the 243.

    SCRATCH THAT!

    The above would be with expanded wilds but you mean single wilds I guess :)

    It would depend on the other symbols on the first four reels as well so it is quite tricky but assuming you did not duplicate any of the winning symbols you would be paid only once for each four of a kind, except where 3 wilds is the greater win.
     
  6. Aug 20, 2010
  7. KasinoKing

    KasinoKing WebMeister & Slotaholic.. CAG MM PABnonaccred webmeister

    Occupation:
    House-Husband and Casino Advisor
    Location:
    Bexhill on sea, England
    If you are talking about the normal wilds (not stacked), then yes, your win should be only 3 wilds = 75 x coins bet. (plus some other 3 of a kind wins).
    That's because all slots state "only the highest win per line is paid".
    All the 4 symbol combinations made with the 3 wilds are lower; 4 x 9 and 4 x 10 = 10 x bet, 4 x castle = 60 x coins bet.

    If they were "stacked wilds" during the Wild Storm feature, your win would be 27 x 3 wilds with no other wins counting, for the same reason.
    So that would be (27 x 75) = 2025 x coins bet.

    I'm pretty sure that's how it works.

    KK
     
  8. Aug 23, 2010
  9. Setag

    Setag Dormant account

    Occupation:
    Game Designer
    Location:
    London
    So what would happen if this spun in?

    9 J A B
    W W W C
    10 Q K T

    The payouts are:

    3x Wild = 75
    4x Boat (B) = 60
    4x Castle(C) = 60
    4x Thor (T) = 100

    The 3x Wild payout is better than Boat or Castle, but surely it can only pay out once in a 243 ways game.
     
  10. Aug 23, 2010
  11. Simmo!

    Simmo! Moderator Staff Member

    Occupation:
    Web Dev.
    Location:
    England
    It would actually pay:

    3 x Wild
    4 x Castle (or Boat as they both pay the same)
    4 x Thor

    And in addition you would also be gettting:

    3 x 9
    3 x 10
    3x J
    3 x Q
    3 x K
    3 x A
     
  12. Aug 23, 2010
  13. Setag

    Setag Dormant account

    Occupation:
    Game Designer
    Location:
    London
    Sorry to clarify do you mean that you can get only 3 wins which involve 4 symbols e.g.:

    3 x Wild
    4 x Castle
    4 x Thor

    Or do you mean getting 4 wins:

    3 x Wild
    4 x Boat
    4 x Castle
    4 x Thor

    If you mean you can only get 3 wins, and it decides that only Boat or Castle will be substituted and not the other is that not very odd? What would make it decide? Why wouldn't the 3 wins be:

    3 x Wild
    3 x Wild
    4 x Thor

    as this is the best payout for the player?
     
  14. Aug 23, 2010
  15. Simmo!

    Simmo! Moderator Staff Member

    Occupation:
    Web Dev.
    Location:
    England
    Theoretically you'd get 3 wilds, 4 boats, 4 castles and 4 Thors, but because the 3 wilds are on the same line as those, and pays more, it will count that INSTEAD of one of those wins because of the general slot rule that only the highest win on a payline counts.
     
  16. Aug 23, 2010
  17. Rusty

    Rusty Banned User - repetitive flaming

    Occupation:
    IT
    Location:
    Manchester UK
    I will try and simplify how to work it out as it is not obvious unless you do the necessary calculations.

    There are 3 stop positions on each reel that can contribute toward a win.
    If you think of the top symbol on each reel being in position 1 the middle in position 2 and the bottom in position 3 you can then see how wins are made up.
    The first number is the position of reel 1(1=top,2= middle,3= bottom) the second number is the same for reel 2 and 3rd number the same for reel 3.
    The "-" is to separate each combination and "--" to separate blocks of 3.
    Note were only dealing with the first 3 reels here.

    1,1,1-1,1,2-1,1,3 --1,2,1-1,2,2-1,2,3 -- 1,3,1-1,3,2-1,3,3
    2,1,1-2,1,2-2,1,3 --2,2,1-2,2,2-2,2,3 -- 2,3,1-2,3,2-2,3,3
    3,1,1-3,1,2-3,1,3 --3,2,1-3,2,2-3,2,3 -- 3,3,1-3,3,2-3,3,3

    As you can see these are the 27 possible combinations of the first 3 reels (3x3x3=27)

    Setags example was (4 reels in play) but we can still see how the wins work.

    Example stop positions for reels
    1 2 3 4
    9 J A B
    W W W C
    10 Q K T

    So using our table we can then see exactly what combinations we are looking at.

    1,1,1-1,1,2-1,1,3 --1,2,1-1,2,2-1,2,3 -- 1,3,1-1,3,2-1,3,3
    2,1,1-2,1,2-2,1,3 --2,2,1-2,2,2-2,2,3 -- 2,3,1-2,3,2-2,3,3
    3,1,1-3,1,2-3,1,3 --3,2,1-3,2,2-3,2,3 -- 3,3,1-3,3,2-3,3,3

    Translates to (Where * shows winning combination);

    9,J,A-9,J,W-9,J,K--9,W,A-9,W,W*-9,W,K--9,Q,A-9,Q,W-9,Q,K
    W,J,A-W,J,W*-W,J,K--W,W,A*-W,W,W*-W,W,K*--W,Q,A-W,Q,W*-W,Q,K
    10,J,A-10,J,W-10,J,K--10,W,A-10,W,W*-10,W,K--10,Q,A-10,Q,W-10,Q,K

    We can now clearly see that when substituting the (W)ild symbol for winning symbols we have.

    9,9,9
    J,J,J
    A,A,A
    W,W,W
    K,K,K
    Q,Q,Q
    10,10,10

    The 4th reel was;
    B
    C
    T

    So since we already have above the only winning combinations we simply need to add this on and see if it contributes to four of a kind.
    (This now makes total combinations 27x3=81)

    9,9,9,B-9,9,9,C-9,9,9,T = 3x three 9's win

    J,J,J,B-J,J,J,C-J,J,J,T = 3x three J's win

    A,A,A,B-A,A,A,C-A,A,A,T = 3x three A's win

    W,W,W,B-W,W,W,C-W,W,W,T = 3x three W's win or 1x four B win, 1x four C win, 1x four T win (largest win pays only)

    K,K,K,B-K,K,K,C-K,K,K,T = 3x three K's win

    Q,Q,Q,B-Q,Q,Q,C-Q,Q,Q,T = 3x three Q's win

    10,10,10,B-10,10,10,C-10,10,10,T = 3x three 10's win

    So Simmo is right and it would only pay 1 x four castle, 1 x four boat and 1 x four Thor.
    This is because the 3 wilds are only represented on one line(2,2,2) going into the fourth reel and each of these symbols is represented only once.
    So their winning combinations are 2,2,2,1-2,2,2,2-2,2,2,3 respectively
    If the boat,castle or Thor symbols were on reel 1,2 or 3 you would then get multiple wins and also obviously any other wild would do the same thing.

    Hope this helps because it can be quite complicated.

    EDIT.

    I read Simmo's post as stating there were four castle wins etc but now realise he means 1 win of castles etc so I have edited my post to reflect this.
     
    Last edited: Aug 23, 2010

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