thank so much INET, 3 months playing there, my first RJ

Ok, so are you suggesting the system pre determines when it's going to pay you a RJ ? That's to say, the system 'says' - OK, when this customer has staked $20,000 total, he/she will get RJ. And if that's the case...1000 spins @ 20 or 100,000 spins @ 20 cents. Therefor, it's not the total amount of spins, but the total staked...and each customer has a different amount they need to stake before hitting an RJ, which in return is reset after a RJ win.

Heya,

That's not what's being stated.

The random jackpot evaluation is a test at the end of any given paid spin by an individual payer to see whether or not that player has won the jackpot.

The chance to win the jackpot is (n)
(n) is based on a bet of, say, $1, for ease of calculation

If a player bets $1, they have (n) chance to trigger and be awarded the random jackpot
If a player bets $5, they have (n*5) chance to win
If a player bets 20c, they have (n/5) chance to win

Each evaluation is independent and does not change based on anything other than the size of that individual bet.

Woooof
 
iNetBet has been Accredited at Casinomeister for nearly 20 years.
Heya,

That's not what's being stated.

The random jackpot evaluation is a test at the end of any given paid spin by an individual payer to see whether or not that player has won the jackpot.

The chance to win the jackpot is (n)
(n) is based on a bet of, say, $1, for ease of calculation

If a player bets $1, they have (n) chance to trigger and be awarded the random jackpot
If a player bets $5, they have (n*5) chance to win
If a player bets 20c, they have (n/5) chance to win

Each evaluation is independent and does not change based on anything other than the size of that individual bet.

Woooof

Well, I understand the math and it's another way of putting things I suppose...But just to clarify my post- I wasn't suggesting that's how it works, merely asking a question.

In respect of what you've said, and assuming it works exactly as you say...then RJ's actually 'work' on individual spins? They'd surely hit more often than they do if that were the case...mathematically speaking...unless of course (and even if the maximum stake was $20) the n threshold is $500...translating into a 20c bet being n (minus) 2500 and so on :)
 
Well, I understand the math and it's another way of putting things I suppose...But just to clarify my post- I wasn't suggesting that's how it works, merely asking a question.

In respect of what you've said, and assuming it works exactly as you say...then RJ's actually 'work' on individual spins? They'd surely hit more often than they do if that were the case...mathematically speaking...unless of course (and even if the maximum stake was $20) the n threshold is $500...translating into a 20c bet being n (minus) 2500 and so on :)

Heya,

The (n) might actually be, for example, 1 in 250,000 (for a bet size of $1)

If it was a $20 bet (n) would then be a 1 in 12500 chance, and conversely if it was a 20c bet (n) would become 1 in 1.25M

If an average trigger value is, say $3500, then this would contribute 1.4% of the game RTP (probability of trigger * value of prize), or (0.000004*3500)
This RTP contribution would be constant irrespective of bet size, since the relative probability versus the relative prize would be proportional.

e.g.: On a $20 bet the odds would become 0.00008 (1 in 12500) multiplied by the relative prize (3500/20) = 175, thus 0.00008*175 = 1.4%
On a 20c bet in this scenario it would be 0.0000008*17500 = 1.4%

These are examples only, but the latest game release does say that random jackpot RTP contribution is no more than 1.5% of the total (including both seed and increment)

Woooof

Edit: It's important to remember though that an "average trigger value" is a result of the test of the chance to trigger, rather than being a range-based jackpot or determinant.
So at the end of any paid spin it's purely a test of 1 in (n) to see whether a player wins the jackpot.
 
Last edited:
Heya,

The (n) might actually be, for example, 1 in 250,000 (for a bet size of $1)

If it was a $20 bet (n) would then be a 1 in 12500 chance, and conversely if it was a 20c bet (n) would become 1 in 1.25M

If an average trigger value is, say $3500, then this would contribute 1.4% of the game RTP (probability of trigger * value of prize), or (0.000004*3500)
This RTP contribution would be constant irrespective of bet size, since the relative probability versus the relative prize would be proportional.

e.g.: On a $20 bet the odds would become 0.00008 (1 in 12500) multiplied by the relative prize (3500/20) = 175, thus 0.00008*175 = 1.4%
On a 20c bet in this scenario it would be 0.0000008*17500 = 1.4%

These are examples only, but the latest game release does say that random jackpot RTP contribution is no more than 1.5% of the total (including both seed and increment)

Woooof

Edit: It's important to remember though that an "average trigger value" is a result of the test of the chance to trigger, rather than being a range-based jackpot or determinant.
So at the end of any paid spin it's purely a test of 1 in (n) to see whether a player wins the jackpot.

Nothing more to be added here then :) I think with all said and done, it's smiply down to luck and bugger all else ;)
 
3000$ on 10$ bet is only 300*bet-size. You can lose that on slots again in a few hours actually. Remember that, dont play them back if you actually are ahead.

Sorry to be a party pooper.
 
thanks zoozie

I have cashed out them and left 250$ to play with then cashed out another 2000.

but yes, it is a small RJ. but a win is a win.
 
iNetBet has been Accredited at Casinomeister for nearly 20 years.

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