# Looking for Math help

#### phynqster

##### Experienced Member
Looking for help from some math experts out there. Since most players play slots till they get down to zero balance. Could someone tell me what the # of spin difference would be on say a 1.00 pull slot that pays 98% 95% or 91%. Not what payouts are excpected but how many pulls a player gets before going broke. Yes, it means they are redepositing their wins. Hope this is enough information.

This is easy. The expected number of spins is simply the player's bankroll divided by the house edge (expressed as a decimal). E.g., if the player has \$50 and plays on a machine with 95% return, then the house edge is 5%=0.05, so the player's expected number of spins is 50/0.05=1000. This is just an average, most of them will bust out much more quickly, but there will be a few lucky ones who pull up the average.

This is easy. The expected number of spins is simply the player's bankroll divided by the house edge (expressed as a decimal). E.g., if the player has \$50 and plays on a machine with 95% return, then the house edge is 5%=0.05, so the player's expected number of spins is 50/0.05=1000. This is just an average, most of them will bust out much more quickly, but there will be a few lucky ones who pull up the average.

That is true but the lower your wager per spin, the less of a variance there will be on the average number of spins. In other words if you bet the minimum you are much more likely to get your 1000 spins than if you bet higher.

Note though that the house edge takes into account paying jackpots which if paid would mean you would get pleanty more than your 1000 spins in total. Therefore it is probably worth calculating the number of estimated spins with a slightly higher house edge