any maths brains out there ?

pinkfloyd

Dormant Account
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Jul 13, 2009
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if i lay 3 rows of cards on the table
a 2 3
a 2 3
a 2 3

shuffle each row up (never mixing them all each row will always contain an a 2 3 )
and gave you one pick from each row

whats the odds of picking a a a from each row ?

now if we repeated that 9 times
whats the odds of picking aaa from each row 9 times straight ?

thanks to any superbrains who can tell me cheers
 
I would say:

3 times in a row = 1/3 * 1/3 * 1/3 = 3.7%

9 times in a row = 1/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 * 1/3 = 0.0051% (that's when hell freezes over) :D

Every additional pick you should divide by 3 (or multiply by 1/3)
 
First pick would be 1 in 3, second pick 1 in 3, third pick 1 in 3. If each row remained the same then each card has an equal chance of being drawn each time, so it's a constant. Not sure of the math of getting A A A each time over 3 attempts, nor the odds of drawing A A A after 1 attempt, but in theorey it's a solid 33.33333% each time you draw a card to get an A.
 
thanks for the replies

i had 8 bonus rounds on a slot that gives you 3 picks
each time i picked the lowest spins , the lowest multiplier and lowest bonus coins

in one session in a row , havent hit it the 9th time yet lol
 
I'm not overly convinced that bonus rounds where you 'pick' a win are truly random, I think it's pre-determined, otherwise how could the RTP be effectively calculated
 
LOL for 8 times

0,00000000000354067784%
or 1 in 282 431 795 927.

Of course pick bonuses are heavily weighted so its impossible to say what the true odds are for your "picks".
 

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